13111300101301 has 2 divisors, whose sum is σ = 13111300101302. Its totient is φ = 13111300101300.

The previous prime is 13111300101283. The next prime is 13111300101311. The reversal of 13111300101301 is 10310100311131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12479608957201 + 631691144100 = 3532649^2 + 794790^2 .

It is an emirp because it is prime and its reverse (10310100311131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13111300101301 - 2²³ = 13111291712693 is a prime.

It is a super-2 number, since 2×13111300101301² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111300101311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555650050650 + 6555650050651.

It is an arithmetic number, because the mean of its divisors is an integer number (6555650050651).

Almost surely, 2^{13111300101301} is an apocalyptic number.

It is an amenable number.

13111300101301 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111300101301 is an equidigital number, since it uses as much as digits as its factorization.

13111300101301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 13111300101301 its reverse (10310100311131), we get a palindrome (23421400412432).

The spelling of 13111300101301 in words is "thirteen trillion, one hundred eleven billion, three hundred million, one hundred one thousand, three hundred one".