13111312024140 has 384 divisors, whose sum is σ = 41154040811520. Its totient is φ = 3091694592000.

The previous prime is 13111312024133. The next prime is 13111312024207. The reversal of 13111312024140 is 4142021311131.

It is a self number, because there is not a number n which added to its sum of digits gives 13111312024140.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 4979608264 + ... + 4979610896.

It is an arithmetic number, because the mean of its divisors is an integer number (107171981280).

Almost surely, 2^{13111312024140} is an apocalyptic number.

13111312024140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13111312024140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20577020405760).

13111312024140 is an abundant number, since it is smaller than the sum of its proper divisors (28042728787380).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13111312024140 is a wasteful number, since it uses less digits than its factorization.

13111312024140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3633 (or 3631 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 13111312024140 its reverse (4142021311131), we get a palindrome (17253333335271).

The spelling of 13111312024140 in words is "thirteen trillion, one hundred eleven billion, three hundred twelve million, twenty-four thousand, one hundred forty".