13111314023 has 2 divisors, whose sum is σ = 13111314024. Its totient is φ = 13111314022.

The previous prime is 13111314017. The next prime is 13111314049. The reversal of 13111314023 is 32041311131.

It is a weak prime.

It is an emirp because it is prime and its reverse (32041311131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13111314023 - 2⁶ = 13111313959 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13111313986 and 13111314004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111314823) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555657011 + 6555657012.

It is an arithmetic number, because the mean of its divisors is an integer number (6555657012).

Almost surely, 2^13111314023 is an apocalyptic number.

13111314023 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111314023 is an equidigital number, since it uses as much as digits as its factorization.

13111314023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 13111314023 its reverse (32041311131), we get a palindrome (45152625154).

The spelling of 13111314023 in words is "thirteen billion, one hundred eleven million, three hundred fourteen thousand, twenty-three".