Base | Representation |
---|---|
bin | 1011111011001011011110… |
… | …1101011010000111111001 |
3 | 1201102102121121002101121021 |
4 | 2332302313231122013321 |
5 | 3204303442003241101 |
6 | 43515131444142441 |
7 | 2522155534620313 |
oct | 276626755320771 |
9 | 51372547071537 |
10 | 13111322321401 |
11 | 41a5531703507 |
12 | 157908b397a21 |
13 | 741514107205 |
14 | 33483ca9a7b3 |
15 | 17b0c78cd5a1 |
hex | becb7b5a1f9 |
13111322321401 has 2 divisors, whose sum is σ = 13111322321402. Its totient is φ = 13111322321400.
The previous prime is 13111322321309. The next prime is 13111322321501. The reversal of 13111322321401 is 10412322311131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11205762945001 + 1905559376400 = 3347501^2 + 1380420^2 .
It is a cyclic number.
It is not a de Polignac number, because 13111322321401 - 211 = 13111322319353 is a prime.
It is not a weakly prime, because it can be changed into another prime (13111322321501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555661160700 + 6555661160701.
It is an arithmetic number, because the mean of its divisors is an integer number (6555661160701).
Almost surely, 213111322321401 is an apocalyptic number.
It is an amenable number.
13111322321401 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111322321401 is an equidigital number, since it uses as much as digits as its factorization.
13111322321401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 13111322321401 its reverse (10412322311131), we get a palindrome (23523644632532).
The spelling of 13111322321401 in words is "thirteen trillion, one hundred eleven billion, three hundred twenty-two million, three hundred twenty-one thousand, four hundred one".
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