Base | Representation |
---|---|
bin | 1011111011001011110001… |
… | …1101100100000111111100 |
3 | 1201102102211011010020100200 |
4 | 2332302330131210013330 |
5 | 3204304122411213030 |
6 | 43515143413123500 |
7 | 2522160523421265 |
oct | 276627435440774 |
9 | 51372734106320 |
10 | 13111402054140 |
11 | 41a5572711935 |
12 | 15790b2029590 |
13 | 7415277a2a50 |
14 | 3348494d396c |
15 | 17b0ce8ccd60 |
hex | becbc7641fc |
13111402054140 has 288 divisors, whose sum is σ = 43808373685440. Its totient is φ = 3154374807552.
The previous prime is 13111402054133. The next prime is 13111402054169. The reversal of 13111402054140 is 4145020411131.
It is a happy number.
13111402054140 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 1 + 40 + 205 + 414 + 0 = 666.
It is a super-2 number, since 2×131114020541402 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 23609904 + ... + 24158856.
It is an arithmetic number, because the mean of its divisors is an integer number (152112408630).
Almost surely, 213111402054140 is an apocalyptic number.
13111402054140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13111402054140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21904186842720).
13111402054140 is an abundant number, since it is smaller than the sum of its proper divisors (30696971631300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13111402054140 is a wasteful number, since it uses less digits than its factorization.
13111402054140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 549213 (or 549208 counting only the distinct ones).
The product of its (nonzero) digits is 1920, while the sum is 27.
Adding to 13111402054140 its reverse (4145020411131), we get a palindrome (17256422465271).
The spelling of 13111402054140 in words is "thirteen trillion, one hundred eleven billion, four hundred two million, fifty-four thousand, one hundred forty".
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