13111402130 has 32 divisors (see below), whose sum is σ = 23817701376. Its totient is φ = 5196501184.

The previous prime is 13111402121. The next prime is 13111402207. The reversal of 13111402130 is 3120411131.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13111402099 and 13111402108.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 517007 + ... + 541773.

It is an arithmetic number, because the mean of its divisors is an integer number (744303168).

Almost surely, 2^13111402130 is an apocalyptic number.

13111402130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13111402130 is a deficient number, since it is larger than the sum of its proper divisors (10706299246).

13111402130 is a wasteful number, since it uses less digits than its factorization.

13111402130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25258.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13111402130 its reverse (3120411131), we get a palindrome (16231813261).

Subtracting from 13111402130 its reverse (3120411131), we obtain a palindrome (9990990999).

The spelling of 13111402130 in words is "thirteen billion, one hundred eleven million, four hundred two thousand, one hundred thirty".