13111402301 has 2 divisors, whose sum is σ = 13111402302. Its totient is φ = 13111402300.

The previous prime is 13111402279. The next prime is 13111402307. The reversal of 13111402301 is 10320411131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12717975076 + 393427225 = 112774^2 + 19835^2 .

It is an emirp because it is prime and its reverse (10320411131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13111402301 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13111402301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111402307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555701150 + 6555701151.

It is an arithmetic number, because the mean of its divisors is an integer number (6555701151).

Almost surely, 2^13111402301 is an apocalyptic number.

It is an amenable number.

13111402301 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111402301 is an equidigital number, since it uses as much as digits as its factorization.

13111402301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13111402301 its reverse (10320411131), we get a palindrome (23431813432).

The spelling of 13111402301 in words is "thirteen billion, one hundred eleven million, four hundred two thousand, three hundred one".