Base | Representation |
---|---|
bin | 11000011011000000… |
… | …00110010110001111 |
3 | 1020211202110011101101 |
4 | 30031200012112033 |
5 | 203323010422203 |
6 | 10005011123531 |
7 | 642625143112 |
oct | 141540062617 |
9 | 36752404341 |
10 | 13111420303 |
11 | 5619067153 |
12 | 265aba35a7 |
13 | 130c4b3687 |
14 | 8c5490579 |
15 | 51b11041d |
hex | 30d80658f |
13111420303 has 2 divisors, whose sum is σ = 13111420304. Its totient is φ = 13111420302.
The previous prime is 13111420297. The next prime is 13111420327. The reversal of 13111420303 is 30302411131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13111420303 - 29 = 13111419791 is a prime.
It is a super-2 number, since 2×131114203032 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13111400303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555710151 + 6555710152.
It is an arithmetic number, because the mean of its divisors is an integer number (6555710152).
Almost surely, 213111420303 is an apocalyptic number.
13111420303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111420303 is an equidigital number, since it uses as much as digits as its factorization.
13111420303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 13111420303 its reverse (30302411131), we get a palindrome (43413831434).
The spelling of 13111420303 in words is "thirteen billion, one hundred eleven million, four hundred twenty thousand, three hundred three".
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