Base | Representation |
---|---|
bin | 11000011011000000… |
… | …01001011111010100 |
3 | 1020211202110211001000 |
4 | 30031200021133110 |
5 | 203323011330142 |
6 | 10005011303300 |
7 | 642625225455 |
oct | 141540113724 |
9 | 36752424030 |
10 | 13111433172 |
11 | 5619075892 |
12 | 265abaab30 |
13 | 130c4b94a6 |
14 | 8c549512c |
15 | 51b11414c |
hex | 30d8097d4 |
13111433172 has 24 divisors (see below), whose sum is σ = 33992604800. Its totient is φ = 4370477688.
The previous prime is 13111433171. The next prime is 13111433197. The reversal of 13111433172 is 27133411131.
13111433172 is a `hidden beast` number, since 1 + 311 + 14 + 331 + 7 + 2 = 666.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13111433171) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60700972 + ... + 60701187.
Almost surely, 213111433172 is an apocalyptic number.
13111433172 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13111433172 is an abundant number, since it is smaller than the sum of its proper divisors (20881171628).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13111433172 is a wasteful number, since it uses less digits than its factorization.
13111433172 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 121402172 (or 121402164 counting only the distinct ones).
The product of its digits is 1512, while the sum is 27.
The spelling of 13111433172 in words is "thirteen billion, one hundred eleven million, four hundred thirty-three thousand, one hundred seventy-two".
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