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1311151134623 = 11119195557693
BaseRepresentation
bin10011000101000110101…
…100101001011110011111
311122100022101011210012012
4103011012230221132133
5132440214142301443
62442200131101435
7163504355521061
oct23050654513637
94570271153165
101311151134623
114660686a7730
12192139a4187b
139684442a255
144766255b731
152418cdba118
hex13146b2979f

1311151134623 has 4 divisors (see below), whose sum is σ = 1430346692328. Its totient is φ = 1191955576920.

The previous prime is 1311151134613. The next prime is 1311151134659. The reversal of 1311151134623 is 3264311511131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311151134623 - 232 = 1306856167327 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1311151134623.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311151134613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59597778836 + ... + 59597778857.

It is an arithmetic number, because the mean of its divisors is an integer number (357586673082).

Almost surely, 21311151134623 is an apocalyptic number.

1311151134623 is a deficient number, since it is larger than the sum of its proper divisors (119195557705).

1311151134623 is a wasteful number, since it uses less digits than its factorization.

1311151134623 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119195557704.

The product of its digits is 6480, while the sum is 32.

Adding to 1311151134623 its reverse (3264311511131), we get a palindrome (4575462645754).

The spelling of 1311151134623 in words is "one trillion, three hundred eleven billion, one hundred fifty-one million, one hundred thirty-four thousand, six hundred twenty-three".

Divisors: 1 11 119195557693 1311151134623