Base | Representation |
---|---|
bin | 11101110011111110100100… |
… | …110110010010100010010001 |
3 | 122012020111022222102002220111 |
4 | 131303332210312102202101 |
5 | 114141142443434340423 |
6 | 1142505301201241321 |
7 | 36421522454166040 |
oct | 3563764466224221 |
9 | 565214288362814 |
10 | 131115232340113 |
11 | 3886072654185a |
12 | 12857016033241 |
13 | 5821162077958 |
14 | 245402268a557 |
15 | 102591c45560d |
hex | 773fa4d92891 |
131115232340113 has 32 divisors (see below), whose sum is σ = 159490843900416. Its totient is φ = 105220093575168.
The previous prime is 131115232340087. The next prime is 131115232340171. The reversal of 131115232340113 is 311043232511131.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 131115232340113 - 213 = 131115232331921 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131115232341113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 472820820 + ... + 473098042.
It is an arithmetic number, because the mean of its divisors is an integer number (4984088871888).
Almost surely, 2131115232340113 is an apocalyptic number.
It is an amenable number.
131115232340113 is a deficient number, since it is larger than the sum of its proper divisors (28375611560303).
131115232340113 is a wasteful number, since it uses less digits than its factorization.
131115232340113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 298033.
The product of its (nonzero) digits is 6480, while the sum is 31.
Adding to 131115232340113 its reverse (311043232511131), we get a palindrome (442158464851244).
The spelling of 131115232340113 in words is "one hundred thirty-one trillion, one hundred fifteen billion, two hundred thirty-two million, three hundred forty thousand, one hundred thirteen".
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