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131115312115483 is a prime number
BaseRepresentation
bin11101110011111110101001…
…100110100110111100011011
3122012020111112112112010010211
4131303332221212212330123
5114141143124400143413
61142505313131151551
736421524443235223
oct3563765146467433
9565214475463124
10131115312115483
113886076757a213
12128570388a55b7
135821175759a07
14245402d0d5083
15102592446283d
hex773fa99a6f1b

131115312115483 has 2 divisors, whose sum is σ = 131115312115484. Its totient is φ = 131115312115482.

The previous prime is 131115312115471. The next prime is 131115312115549. The reversal of 131115312115483 is 384511213511131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131115312115483 - 25 = 131115312115451 is a prime.

It is a super-2 number, since 2×1311153121154832 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131115312110483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65557656057741 + 65557656057742.

It is an arithmetic number, because the mean of its divisors is an integer number (65557656057742).

Almost surely, 2131115312115483 is an apocalyptic number.

131115312115483 is a deficient number, since it is larger than the sum of its proper divisors (1).

131115312115483 is an equidigital number, since it uses as much as digits as its factorization.

131115312115483 is an evil number, because the sum of its binary digits is even.

The product of its digits is 43200, while the sum is 40.

The spelling of 131115312115483 in words is "one hundred thirty-one trillion, one hundred fifteen billion, three hundred twelve million, one hundred fifteen thousand, four hundred eighty-three".