Base | Representation |
---|---|
bin | 111101000011100111… |
… | …1111010100001110011 |
3 | 110112102211212100221221 |
4 | 1322013033322201303 |
5 | 4122012214134211 |
6 | 140122420125511 |
7 | 12321141405436 |
oct | 1720717724163 |
9 | 415384770857 |
10 | 131118114931 |
11 | 50674837461 |
12 | 214b3236897 |
13 | c4977288bb |
14 | 64bbba181d |
15 | 36260c6c71 |
hex | 1e873fa873 |
131118114931 has 2 divisors, whose sum is σ = 131118114932. Its totient is φ = 131118114930.
The previous prime is 131118114899. The next prime is 131118114943. The reversal of 131118114931 is 139411811131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131118114931 - 25 = 131118114899 is a prime.
It is a super-2 number, since 2×1311181149312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131118114991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65559057465 + 65559057466.
It is an arithmetic number, because the mean of its divisors is an integer number (65559057466).
Almost surely, 2131118114931 is an apocalyptic number.
131118114931 is a deficient number, since it is larger than the sum of its proper divisors (1).
131118114931 is an equidigital number, since it uses as much as digits as its factorization.
131118114931 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2592, while the sum is 34.
The spelling of 131118114931 in words is "one hundred thirty-one billion, one hundred eighteen million, one hundred fourteen thousand, nine hundred thirty-one".
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