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131120011133 is a prime number
BaseRepresentation
bin111101000011101011…
…1001001011101111101
3110112102222102201001122
41322013113021131331
54122013210324013
6140122524520325
712321163463636
oct1720727113575
9415388381048
10131120011133
1150675912071
12214b39b00a5
13c497c40a07
1464bc13688d
15362634da08
hex1e875c977d

131120011133 has 2 divisors, whose sum is σ = 131120011134. Its totient is φ = 131120011132.

The previous prime is 131120011111. The next prime is 131120011147. The reversal of 131120011133 is 331110021131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109827948409 + 21292062724 = 331403^2 + 145918^2 .

It is an emirp because it is prime and its reverse (331110021131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131120011133 - 216 = 131119945597 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131120011733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560005566 + 65560005567.

It is an arithmetic number, because the mean of its divisors is an integer number (65560005567).

Almost surely, 2131120011133 is an apocalyptic number.

It is an amenable number.

131120011133 is a deficient number, since it is larger than the sum of its proper divisors (1).

131120011133 is an equidigital number, since it uses as much as digits as its factorization.

131120011133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 131120011133 its reverse (331110021131), we get a palindrome (462230032264).

The spelling of 131120011133 in words is "one hundred thirty-one billion, one hundred twenty million, eleven thousand, one hundred thirty-three".