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13112011203041 is a prime number
BaseRepresentation
bin1011111011001110000011…
…0001010010000111100001
31201102111101121100012120002
42332303200301102013201
53204311344331444131
643515324053225345
72522211601203512
oct276634061220741
951374347305502
1013112011203041
1141a5855549483
121579242032255
137415c3a5299a
143348a637ca09
1517b1181066cb
hexbece0c521e1

13112011203041 has 2 divisors, whose sum is σ = 13112011203042. Its totient is φ = 13112011203040.

The previous prime is 13112011203001. The next prime is 13112011203043. The reversal of 13112011203041 is 14030211021131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10854817462225 + 2257193740816 = 3294665^2 + 1502396^2 .

It is a cyclic number.

It is not a de Polignac number, because 13112011203041 - 230 = 13110937461217 is a prime.

Together with 13112011203043, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13112011203043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556005601520 + 6556005601521.

It is an arithmetic number, because the mean of its divisors is an integer number (6556005601521).

Almost surely, 213112011203041 is an apocalyptic number.

It is an amenable number.

13112011203041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112011203041 is an equidigital number, since it uses as much as digits as its factorization.

13112011203041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 13112011203041 its reverse (14030211021131), we get a palindrome (27142222224172).

The spelling of 13112011203041 in words is "thirteen trillion, one hundred twelve billion, eleven million, two hundred three thousand, forty-one".