Base | Representation |
---|---|
bin | 1011111011001110000011… |
… | …0001110001001010000111 |
3 | 1201102111101121120122222001 |
4 | 2332303200301301022013 |
5 | 3204311344400031213 |
6 | 43515324100050131 |
7 | 2522211602243263 |
oct | 276634061611207 |
9 | 51374347518861 |
10 | 13112011330183 |
11 | 41a5855625a57 |
12 | 1579242093947 |
13 | 7415c3a9880c |
14 | 3348a63b30a3 |
15 | 17b11812e1dd |
hex | bece0c71287 |
13112011330183 has 2 divisors, whose sum is σ = 13112011330184. Its totient is φ = 13112011330182.
The previous prime is 13112011330073. The next prime is 13112011330241. The reversal of 13112011330183 is 38103311021131.
13112011330183 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13112011330183 - 241 = 10912988074631 is a prime.
It is a super-2 number, since 2×131120113301832 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112011430183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556005665091 + 6556005665092.
It is an arithmetic number, because the mean of its divisors is an integer number (6556005665092).
Almost surely, 213112011330183 is an apocalyptic number.
13112011330183 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112011330183 is an equidigital number, since it uses as much as digits as its factorization.
13112011330183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 28.
The spelling of 13112011330183 in words is "thirteen trillion, one hundred twelve billion, eleven million, three hundred thirty thousand, one hundred eighty-three".
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