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13112012323103 is a prime number
BaseRepresentation
bin1011111011001110000011…
…0101100011100100011111
31201102111101200110002222212
42332303200311203210133
53204311400123314403
643515324133231035
72522211613550141
oct276634065434437
951374350402885
1013112012323103
1141a5856143a51
12157924249247b
137415c4055745
143348a6590c91
1517b1182784d8
hexbece0d6391f

13112012323103 has 2 divisors, whose sum is σ = 13112012323104. Its totient is φ = 13112012323102.

The previous prime is 13112012323037. The next prime is 13112012323127. The reversal of 13112012323103 is 30132321021131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13112012323103 - 222 = 13112008128799 is a prime.

It is a super-2 number, since 2×131120123231032 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13112012323903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556006161551 + 6556006161552.

It is an arithmetic number, because the mean of its divisors is an integer number (6556006161552).

Almost surely, 213112012323103 is an apocalyptic number.

13112012323103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112012323103 is an equidigital number, since it uses as much as digits as its factorization.

13112012323103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 13112012323103 its reverse (30132321021131), we get a palindrome (43244333344234).

The spelling of 13112012323103 in words is "thirteen trillion, one hundred twelve billion, twelve million, three hundred twenty-three thousand, one hundred three".