Base | Representation |
---|---|
bin | 1011111011001110000011… |
… | …0101100011100100011111 |
3 | 1201102111101200110002222212 |
4 | 2332303200311203210133 |
5 | 3204311400123314403 |
6 | 43515324133231035 |
7 | 2522211613550141 |
oct | 276634065434437 |
9 | 51374350402885 |
10 | 13112012323103 |
11 | 41a5856143a51 |
12 | 157924249247b |
13 | 7415c4055745 |
14 | 3348a6590c91 |
15 | 17b1182784d8 |
hex | bece0d6391f |
13112012323103 has 2 divisors, whose sum is σ = 13112012323104. Its totient is φ = 13112012323102.
The previous prime is 13112012323037. The next prime is 13112012323127. The reversal of 13112012323103 is 30132321021131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13112012323103 - 222 = 13112008128799 is a prime.
It is a super-2 number, since 2×131120123231032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112012323903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556006161551 + 6556006161552.
It is an arithmetic number, because the mean of its divisors is an integer number (6556006161552).
Almost surely, 213112012323103 is an apocalyptic number.
13112012323103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112012323103 is an equidigital number, since it uses as much as digits as its factorization.
13112012323103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 13112012323103 its reverse (30132321021131), we get a palindrome (43244333344234).
The spelling of 13112012323103 in words is "thirteen trillion, one hundred twelve billion, twelve million, three hundred twenty-three thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •