1311202113433 has 2 divisors, whose sum is σ = 1311202113434. Its totient is φ = 1311202113432.

The previous prime is 1311202113373. The next prime is 1311202113497. The reversal of 1311202113433 is 3343112021131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1308168637504 + 3033475929 = 1143752^2 + 55077^2 .

It is an emirp because it is prime and its reverse (3343112021131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311202113433 - 2²¹ = 1311200016281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311202113398 and 1311202113407.

It is not a weakly prime, because it can be changed into another prime (1311202113233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655601056716 + 655601056717.

It is an arithmetic number, because the mean of its divisors is an integer number (655601056717).

Almost surely, 2^{1311202113433} is an apocalyptic number.

It is an amenable number.

1311202113433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311202113433 is an equidigital number, since it uses as much as digits as its factorization.

1311202113433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1311202113433 its reverse (3343112021131), we get a palindrome (4654314134564).

The spelling of 1311202113433 in words is "one trillion, three hundred eleven billion, two hundred two million, one hundred thirteen thousand, four hundred thirty-three".