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131120341243181 is a prime number
BaseRepresentation
bin11101110100000011010101…
…010111001101010100101101
3122012020222112000201021101122
4131310003111113031110231
5114141233424324240211
61142511504142550325
736422063201146133
oct3564032527152455
9565228460637348
10131120341243181
11388629083712a4
1212858000b983a5
135821797646514
142454388db9753
151025b1ac1e6db
hex7740d55cd52d

131120341243181 has 2 divisors, whose sum is σ = 131120341243182. Its totient is φ = 131120341243180.

The previous prime is 131120341243147. The next prime is 131120341243267. The reversal of 131120341243181 is 181342143021131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124437728487556 + 6682612755625 = 11155166^2 + 2585075^2 .

It is a cyclic number.

It is not a de Polignac number, because 131120341243181 - 218 = 131120340981037 is a prime.

It is a super-2 number, since 2×1311203412431812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131120341213181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560170621590 + 65560170621591.

It is an arithmetic number, because the mean of its divisors is an integer number (65560170621591).

Almost surely, 2131120341243181 is an apocalyptic number.

It is an amenable number.

131120341243181 is a deficient number, since it is larger than the sum of its proper divisors (1).

131120341243181 is an equidigital number, since it uses as much as digits as its factorization.

131120341243181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 35.

The spelling of 131120341243181 in words is "one hundred thirty-one trillion, one hundred twenty billion, three hundred forty-one million, two hundred forty-three thousand, one hundred eighty-one".