131121003001013 has 2 divisors, whose sum is σ = 131121003001014. Its totient is φ = 131121003001012.

The previous prime is 131121003000989. The next prime is 131121003001019. The reversal of 131121003001013 is 310100300121131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121648039359889 + 9472963641124 = 11029417^2 + 3077818^2 .

It is a cyclic number.

It is not a de Polignac number, because 131121003001013 - 2¹⁰ = 131121002999989 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131121003000982 and 131121003001000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131121003001019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560501500506 + 65560501500507.

It is an arithmetic number, because the mean of its divisors is an integer number (65560501500507).

Almost surely, 2^{131121003001013} is an apocalyptic number.

It is an amenable number.

131121003001013 is a deficient number, since it is larger than the sum of its proper divisors (1).

131121003001013 is an equidigital number, since it uses as much as digits as its factorization.

131121003001013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 131121003001013 its reverse (310100300121131), we get a palindrome (441221303122144).

The spelling of 131121003001013 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, three million, one thousand, thirteen".