131121020031120 has 240 divisors, whose sum is σ = 503308338204672. Its totient is φ = 29967340170240.

The previous prime is 131121020031059. The next prime is 131121020031137. The reversal of 131121020031120 is 21130020121131.

131121020031120 is a `hidden beast` number, since 1 + 31 + 121 + 0 + 200 + 311 + 2 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (240).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 131121020031093 and 131121020031102.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 46308529 + ... + 49058351.

Almost surely, 2^{131121020031120} is an apocalyptic number.

131121020031120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131121020031120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (251654169102336).

131121020031120 is an abundant number, since it is smaller than the sum of its proper divisors (372187318173552).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131121020031120 is a wasteful number, since it uses less digits than its factorization.

131121020031120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2759310 (or 2759301 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 131121020031120 its reverse (21130020121131), we get a palindrome (152251040152251).

The spelling of 131121020031120 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, twenty million, thirty-one thousand, one hundred twenty".