1311210301417 has 2 divisors, whose sum is σ = 1311210301418. Its totient is φ = 1311210301416.

The previous prime is 1311210301411. The next prime is 1311210301433. The reversal of 1311210301417 is 7141030121131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1038328392256 + 272881909161 = 1018984^2 + 522381^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311210301417 - 2³ = 1311210301409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311210301391 and 1311210301400.

It is not a weakly prime, because it can be changed into another prime (1311210301411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655605150708 + 655605150709.

It is an arithmetic number, because the mean of its divisors is an integer number (655605150709).

Almost surely, 2^{1311210301417} is an apocalyptic number.

It is an amenable number.

1311210301417 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311210301417 is an equidigital number, since it uses as much as digits as its factorization.

1311210301417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 25.

Adding to 1311210301417 its reverse (7141030121131), we get a palindrome (8452240422548).

The spelling of 1311210301417 in words is "one trillion, three hundred eleven billion, two hundred ten million, three hundred one thousand, four hundred seventeen".