Base | Representation |
---|---|
bin | 11101110100000100000101… |
… | …110001111010011010110101 |
3 | 122012021001121122012201212120 |
4 | 131310010011301322122311 |
5 | 114141242110302100010 |
6 | 1142512120521310153 |
7 | 36422122263510453 |
oct | 3564040561723265 |
9 | 565231548181776 |
10 | 131121153550005 |
11 | 38863194948453 |
12 | 128581a9035359 |
13 | 5821896a17c48 |
14 | 2454424c299d3 |
15 | 1025b671c7e70 |
hex | 774105c7a6b5 |
131121153550005 has 16 divisors (see below), whose sum is σ = 210880860429120. Its totient is φ = 69568943643648.
The previous prime is 131121153549983. The next prime is 131121153550039. The reversal of 131121153550005 is 500055351121131.
It is not a de Polignac number, because 131121153550005 - 27 = 131121153549877 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22646137615 + ... + 22646143404.
It is an arithmetic number, because the mean of its divisors is an integer number (13180053776820).
Almost surely, 2131121153550005 is an apocalyptic number.
131121153550005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
131121153550005 is a deficient number, since it is larger than the sum of its proper divisors (79759706879115).
131121153550005 is a wasteful number, since it uses less digits than its factorization.
131121153550005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45292281220.
The product of its (nonzero) digits is 11250, while the sum is 33.
The spelling of 131121153550005 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, one hundred fifty-three million, five hundred fifty thousand, five".
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