Base | Representation |
---|---|
bin | 11101110100000100000101… |
… | …110001111010011010011111 |
3 | 122012021001121122012201211202 |
4 | 131310010011301322122133 |
5 | 114141242110302044413 |
6 | 1142512120521310115 |
7 | 36422122263510422 |
oct | 3564040561723237 |
9 | 565231548181752 |
10 | 131121153549983 |
11 | 38863194948433 |
12 | 128581a903533b |
13 | 5821896a17c2c |
14 | 2454424c299b9 |
15 | 1025b671c7e58 |
hex | 774105c7a69f |
131121153549983 has 2 divisors, whose sum is σ = 131121153549984. Its totient is φ = 131121153549982.
The previous prime is 131121153549961. The next prime is 131121153550039. The reversal of 131121153549983 is 389945351121131.
It is an a-pointer prime, because the next prime (131121153550039) can be obtained adding 131121153549983 to its sum of digits (56).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131121153549983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131121153549943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560576774991 + 65560576774992.
It is an arithmetic number, because the mean of its divisors is an integer number (65560576774992).
Almost surely, 2131121153549983 is an apocalyptic number.
131121153549983 is a deficient number, since it is larger than the sum of its proper divisors (1).
131121153549983 is an equidigital number, since it uses as much as digits as its factorization.
131121153549983 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3499200, while the sum is 56.
The spelling of 131121153549983 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, one hundred fifty-three million, five hundred forty-nine thousand, nine hundred eighty-three".
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