131121153550039 has 2 divisors, whose sum is σ = 131121153550040. Its totient is φ = 131121153550038.

The previous prime is 131121153549983. The next prime is 131121153550043. The reversal of 131121153550039 is 930055351121131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131121153550039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131121153549983 and 131121153550010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131121153550099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560576775019 + 65560576775020.

It is an arithmetic number, because the mean of its divisors is an integer number (65560576775020).

Almost surely, 2^{131121153550039} is an apocalyptic number.

131121153550039 is a deficient number, since it is larger than the sum of its proper divisors (1).

131121153550039 is an equidigital number, since it uses as much as digits as its factorization.

131121153550039 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60750, while the sum is 40.

The spelling of 131121153550039 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, one hundred fifty-three million, five hundred fifty thousand, thirty-nine".