Base | Representation |
---|---|
bin | 11101110100000100000101… |
… | …110100000101111001110001 |
3 | 122012021001121200021202120201 |
4 | 131310010011310011321301 |
5 | 114141242110423340304 |
6 | 1142512120541435201 |
7 | 36422122301410231 |
oct | 3564040564057161 |
9 | 565231550252521 |
10 | 131121154121329 |
11 | 388631951a8719 |
12 | 128581a926bb01 |
13 | 5821896b87cc8 |
14 | 2454424d37cc1 |
15 | 1025b6728c3a4 |
hex | 774105d05e71 |
131121154121329 has 2 divisors, whose sum is σ = 131121154121330. Its totient is φ = 131121154121328.
The previous prime is 131121154121281. The next prime is 131121154121341. The reversal of 131121154121329 is 923121451121131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 66435165703729 + 64685988417600 = 8150777^2 + 8042760^2 .
It is a cyclic number.
It is not a de Polignac number, because 131121154121329 - 213 = 131121154113137 is a prime.
It is not a weakly prime, because it can be changed into another prime (131121154121389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560577060664 + 65560577060665.
It is an arithmetic number, because the mean of its divisors is an integer number (65560577060665).
Almost surely, 2131121154121329 is an apocalyptic number.
It is an amenable number.
131121154121329 is a deficient number, since it is larger than the sum of its proper divisors (1).
131121154121329 is an equidigital number, since it uses as much as digits as its factorization.
131121154121329 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12960, while the sum is 37.
The spelling of 131121154121329 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, one hundred fifty-four million, one hundred twenty-one thousand, three hundred twenty-nine".
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