Base | Representation |
---|---|
bin | 11101110100000100000101… |
… | …110100000101111001000001 |
3 | 122012021001121200021202111221 |
4 | 131310010011310011321001 |
5 | 114141242110423340111 |
6 | 1142512120541435041 |
7 | 36422122301410132 |
oct | 3564040564057101 |
9 | 565231550252457 |
10 | 131121154121281 |
11 | 388631951a8685 |
12 | 128581a926ba81 |
13 | 5821896b87c8c |
14 | 2454424d37c89 |
15 | 1025b6728c371 |
hex | 774105d05e41 |
131121154121281 has 2 divisors, whose sum is σ = 131121154121282. Its totient is φ = 131121154121280.
The previous prime is 131121154121249. The next prime is 131121154121329. The reversal of 131121154121281 is 182121451121131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 118329687423025 + 12791466698256 = 10877945^2 + 3576516^2 .
It is a cyclic number.
It is not a de Polignac number, because 131121154121281 - 25 = 131121154121249 is a prime.
It is a super-2 number, since 2×1311211541212812 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131121154121231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560577060640 + 65560577060641.
It is an arithmetic number, because the mean of its divisors is an integer number (65560577060641).
Almost surely, 2131121154121281 is an apocalyptic number.
It is an amenable number.
131121154121281 is a deficient number, since it is larger than the sum of its proper divisors (1).
131121154121281 is an equidigital number, since it uses as much as digits as its factorization.
131121154121281 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3840, while the sum is 34.
The spelling of 131121154121281 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, one hundred fifty-four million, one hundred twenty-one thousand, two hundred eighty-one".
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