1311213030000 has 400 divisors, whose sum is σ = 4376518265856. Its totient is φ = 337910400000.

The previous prime is 1311213029983. The next prime is 1311213030007. The reversal of 1311213030000 is 303121131.

It is a tau number, because it is divible by the number of its divisors (400).

It is a super-2 number, since 2×1311213030000² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311213030007) by changing a digit.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 167606089 + ... + 167613911.

Almost surely, 2^{1311213030000} is an apocalyptic number.

1311213030000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1311213030000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2188259132928).

1311213030000 is an abundant number, since it is smaller than the sum of its proper divisors (3065305235856).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311213030000 is a wasteful number, since it uses less digits than its factorization.

1311213030000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8042 (or 8021 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1311213030000 its reverse (303121131), we get a palindrome (1311516151131).

The spelling of 1311213030000 in words is "one trillion, three hundred eleven billion, two hundred thirteen million, thirty thousand".