Base | Representation |
---|---|
bin | 11101110100000100001110… |
… | …110001110010011101111011 |
3 | 122012021002000011021102022121 |
4 | 131310010032301302131323 |
5 | 114141242412423344004 |
6 | 1142512143513102111 |
7 | 36422126105616136 |
oct | 3564041661623573 |
9 | 565232004242277 |
10 | 131121304512379 |
11 | 38863262087745 |
12 | 1285822b6b7937 |
13 | 58218bc092bac |
14 | 245443acc521d |
15 | 1025b75597854 |
hex | 77410ec7277b |
131121304512379 has 2 divisors, whose sum is σ = 131121304512380. Its totient is φ = 131121304512378.
The previous prime is 131121304512371. The next prime is 131121304512463. The reversal of 131121304512379 is 973215403121131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131121304512379 - 23 = 131121304512371 is a prime.
It is not a weakly prime, because it can be changed into another prime (131121304512371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560652256189 + 65560652256190.
It is an arithmetic number, because the mean of its divisors is an integer number (65560652256190).
Almost surely, 2131121304512379 is an apocalyptic number.
131121304512379 is a deficient number, since it is larger than the sum of its proper divisors (1).
131121304512379 is an equidigital number, since it uses as much as digits as its factorization.
131121304512379 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 43.
The spelling of 131121304512379 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, three hundred four million, five hundred twelve thousand, three hundred seventy-nine".
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