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131121304512463 is a prime number
BaseRepresentation
bin11101110100000100001110…
…110001110010011111001111
3122012021002000011021102102201
4131310010032301302133033
5114141242412423344323
61142512143513102331
736422126105616316
oct3564041661623717
9565232004242381
10131121304512463
1138863262087811
121285822b6b79a7
1358218bc092c45
14245443acc527d
151025b755978ad
hex77410ec727cf

131121304512463 has 2 divisors, whose sum is σ = 131121304512464. Its totient is φ = 131121304512462.

The previous prime is 131121304512379. The next prime is 131121304512481. The reversal of 131121304512463 is 364215403121131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131121304512463 - 213 = 131121304504271 is a prime.

It is a super-2 number, since 2×1311213045124632 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131121304510463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560652256231 + 65560652256232.

It is an arithmetic number, because the mean of its divisors is an integer number (65560652256232).

Almost surely, 2131121304512463 is an apocalyptic number.

131121304512463 is a deficient number, since it is larger than the sum of its proper divisors (1).

131121304512463 is an equidigital number, since it uses as much as digits as its factorization.

131121304512463 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 37.

Adding to 131121304512463 its reverse (364215403121131), we get a palindrome (495336707633594).

The spelling of 131121304512463 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, three hundred four million, five hundred twelve thousand, four hundred sixty-three".