Base | Representation |
---|---|
bin | 11101110100000100001110… |
… | …110001110010011111001111 |
3 | 122012021002000011021102102201 |
4 | 131310010032301302133033 |
5 | 114141242412423344323 |
6 | 1142512143513102331 |
7 | 36422126105616316 |
oct | 3564041661623717 |
9 | 565232004242381 |
10 | 131121304512463 |
11 | 38863262087811 |
12 | 1285822b6b79a7 |
13 | 58218bc092c45 |
14 | 245443acc527d |
15 | 1025b755978ad |
hex | 77410ec727cf |
131121304512463 has 2 divisors, whose sum is σ = 131121304512464. Its totient is φ = 131121304512462.
The previous prime is 131121304512379. The next prime is 131121304512481. The reversal of 131121304512463 is 364215403121131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131121304512463 - 213 = 131121304504271 is a prime.
It is a super-2 number, since 2×1311213045124632 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131121304510463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560652256231 + 65560652256232.
It is an arithmetic number, because the mean of its divisors is an integer number (65560652256232).
Almost surely, 2131121304512463 is an apocalyptic number.
131121304512463 is a deficient number, since it is larger than the sum of its proper divisors (1).
131121304512463 is an equidigital number, since it uses as much as digits as its factorization.
131121304512463 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 37.
Adding to 131121304512463 its reverse (364215403121131), we get a palindrome (495336707633594).
The spelling of 131121304512463 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, three hundred four million, five hundred twelve thousand, four hundred sixty-three".
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