131121304512441 has 4 divisors (see below), whose sum is σ = 174828406016592. Its totient is φ = 87414203008292.

The previous prime is 131121304512379. The next prime is 131121304512463. The reversal of 131121304512441 is 144215403121131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131121304512441 - 2¹⁷ = 131121304381369 is a prime.

It is not an unprimeable number, because it can be changed into a prime (131121304512481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21853550752071 + ... + 21853550752076.

It is an arithmetic number, because the mean of its divisors is an integer number (43707101504148).

Almost surely, 2^{131121304512441} is an apocalyptic number.

It is an amenable number.

131121304512441 is a deficient number, since it is larger than the sum of its proper divisors (43707101504151).

131121304512441 is an equidigital number, since it uses as much as digits as its factorization.

131121304512441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43707101504150.

The product of its (nonzero) digits is 11520, while the sum is 33.

Adding to 131121304512441 its reverse (144215403121131), we get a palindrome (275336707633572).

The spelling of 131121304512441 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, three hundred four million, five hundred twelve thousand, four hundred forty-one".