131121304512440 has 64 divisors (see below), whose sum is σ = 329327927660160. Its totient is φ = 46571626120320.

The previous prime is 131121304512379. The next prime is 131121304512463. The reversal of 131121304512440 is 44215403121131.

It is a super-2 number, since 2×131121304512440² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131121304512397 and 131121304512406.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3465131834 + ... + 3465169673.

It is an arithmetic number, because the mean of its divisors is an integer number (5145748869690).

Almost surely, 2^{131121304512440} is an apocalyptic number.

131121304512440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131121304512440 is an abundant number, since it is smaller than the sum of its proper divisors (198206623147720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131121304512440 is a wasteful number, since it uses less digits than its factorization.

131121304512440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6930301572 (or 6930301568 counting only the distinct ones).

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 131121304512440 its reverse (44215403121131), we get a palindrome (175336707633571).

The spelling of 131121304512440 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, three hundred four million, five hundred twelve thousand, four hundred forty".