Base | Representation |
---|---|
bin | 10011000101001010011… |
… | …001000110111001110101 |
3 | 11122100110200211000201011 |
4 | 103011022121012321311 |
5 | 132440331024334031 |
6 | 2442210223432221 |
7 | 163506040430560 |
oct | 23051231067165 |
9 | 4570420730634 |
10 | 1311213121141 |
11 | 46609a695060 |
12 | 192156755671 |
13 | 96854221471 |
14 | 4766a8954d7 |
15 | 241935616b1 |
hex | 1314a646e75 |
1311213121141 has 32 divisors (see below), whose sum is σ = 1650345984000. Its totient is φ = 1012028878080.
The previous prime is 1311213121129. The next prime is 1311213121181. The reversal of 1311213121141 is 1411213121131.
It is not a de Polignac number, because 1311213121141 - 29 = 1311213120629 is a prime.
It is a super-2 number, since 2×13112131211412 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311213121181) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3225165 + ... + 3608893.
It is an arithmetic number, because the mean of its divisors is an integer number (51573312000).
Almost surely, 21311213121141 is an apocalyptic number.
1311213121141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1311213121141 is a deficient number, since it is larger than the sum of its proper divisors (339132862859).
1311213121141 is a wasteful number, since it uses less digits than its factorization.
1311213121141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 384169.
The product of its digits is 144, while the sum is 22.
Adding to 1311213121141 its reverse (1411213121131), we get a palindrome (2722426242272).
The spelling of 1311213121141 in words is "one trillion, three hundred eleven billion, two hundred thirteen million, one hundred twenty-one thousand, one hundred forty-one".
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