Base | Representation |
---|---|
bin | 100111000100111… |
… | …1000011001011101 |
3 | 10101101021112021222 |
4 | 1032021320121131 |
5 | 10141132310044 |
6 | 334035503125 |
7 | 44331061601 |
oct | 11611703135 |
9 | 3341245258 |
10 | 1311213149 |
11 | 613166934 |
12 | 307157aa5 |
13 | 17b862a8c |
14 | c61dd501 |
15 | 7a1a78ee |
hex | 4e27865d |
1311213149 has 2 divisors, whose sum is σ = 1311213150. Its totient is φ = 1311213148.
The previous prime is 1311213133. The next prime is 1311213173. The reversal of 1311213149 is 9413121131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1289887225 + 21325924 = 35915^2 + 4618^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311213149 - 24 = 1311213133 is a prime.
It is a super-2 number, since 2×13112131492 = 3438559844220992402, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311213649) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655606574 + 655606575.
It is an arithmetic number, because the mean of its divisors is an integer number (655606575).
Almost surely, 21311213149 is an apocalyptic number.
It is an amenable number.
1311213149 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311213149 is an equidigital number, since it uses as much as digits as its factorization.
1311213149 is an evil number, because the sum of its binary digits is even.
The product of its digits is 648, while the sum is 26.
The square root of 1311213149 is about 36210.6772789463. The cubic root of 1311213149 is about 1094.5218401165.
The spelling of 1311213149 in words is "one billion, three hundred eleven million, two hundred thirteen thousand, one hundred forty-nine".
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