Base | Representation |
---|---|
bin | 111101000011101110… |
… | …0001001100010100011 |
3 | 110112110001220022102201 |
4 | 1322013130021202203 |
5 | 4122014024302042 |
6 | 140123012554031 |
7 | 12321210564064 |
oct | 1720734114243 |
9 | 415401808381 |
10 | 131121322147 |
11 | 50676628052 |
12 | 214b4322917 |
13 | c4982ac66a |
14 | 64bc39856b |
15 | 362650c1b7 |
hex | 1e877098a3 |
131121322147 has 2 divisors, whose sum is σ = 131121322148. Its totient is φ = 131121322146.
The previous prime is 131121322093. The next prime is 131121322231. The reversal of 131121322147 is 741223121131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131121322147 - 215 = 131121289379 is a prime.
It is a super-2 number, since 2×1311213221472 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131121322447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560661073 + 65560661074.
It is an arithmetic number, because the mean of its divisors is an integer number (65560661074).
Almost surely, 2131121322147 is an apocalyptic number.
131121322147 is a deficient number, since it is larger than the sum of its proper divisors (1).
131121322147 is an equidigital number, since it uses as much as digits as its factorization.
131121322147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2016, while the sum is 28.
Adding to 131121322147 its reverse (741223121131), we get a palindrome (872344443278).
The spelling of 131121322147 in words is "one hundred thirty-one billion, one hundred twenty-one million, three hundred twenty-two thousand, one hundred forty-seven".
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