13112133000023 has 2 divisors, whose sum is σ = 13112133000024. Its totient is φ = 13112133000022.

The previous prime is 13112133000011. The next prime is 13112133000037. The reversal of 13112133000023 is 32000033121131.

It is a weak prime.

It is an emirp because it is prime and its reverse (32000033121131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13112133000023 - 2³² = 13107838032727 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13112132999959 and 13112133000004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13112133030023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556066500011 + 6556066500012.

It is an arithmetic number, because the mean of its divisors is an integer number (6556066500012).

Almost surely, 2^{13112133000023} is an apocalyptic number.

13112133000023 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112133000023 is an equidigital number, since it uses as much as digits as its factorization.

13112133000023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 13112133000023 its reverse (32000033121131), we get a palindrome (45112166121154).

The spelling of 13112133000023 in words is "thirteen trillion, one hundred twelve billion, one hundred thirty-three million, twenty-three", and thus it is an aban number.