Base | Representation |
---|---|
bin | 11000011011000101… |
… | …10100010111111001 |
3 | 1020211210210101011202 |
4 | 30031202310113321 |
5 | 203323201224423 |
6 | 10005034303545 |
7 | 642634202222 |
oct | 141542642771 |
9 | 36753711152 |
10 | 13112133113 |
11 | 5619503752 |
12 | 265b287bb5 |
13 | 130c6a2c61 |
14 | 8c55d8249 |
15 | 51b201728 |
hex | 30d8b45f9 |
13112133113 has 2 divisors, whose sum is σ = 13112133114. Its totient is φ = 13112133112.
The previous prime is 13112133107. The next prime is 13112133119. The reversal of 13112133113 is 31133121131.
It is a balanced prime because it is at equal distance from previous prime (13112133107) and next prime (13112133119).
It can be written as a sum of positive squares in only one way, i.e., 11446432144 + 1665700969 = 106988^2 + 40813^2 .
It is a cyclic number.
It is not a de Polignac number, because 13112133113 - 28 = 13112132857 is a prime.
It is not a weakly prime, because it can be changed into another prime (13112133119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556066556 + 6556066557.
It is an arithmetic number, because the mean of its divisors is an integer number (6556066557).
Almost surely, 213112133113 is an apocalyptic number.
It is an amenable number.
13112133113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112133113 is an equidigital number, since it uses as much as digits as its factorization.
13112133113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 162, while the sum is 20.
Adding to 13112133113 its reverse (31133121131), we get a palindrome (44245254244).
The spelling of 13112133113 in words is "thirteen billion, one hundred twelve million, one hundred thirty-three thousand, one hundred thirteen".
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