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1311213403 is a prime number
BaseRepresentation
bin100111000100111…
…1000011101011011
310101101021112122101
41032021320131123
510141132312103
6334035504231
744331062413
oct11611703533
93341245571
101311213403
11613167045
12307158077
1317b862c26
14c61dd643
157a1a7a1d
hex4e27875b

1311213403 has 2 divisors, whose sum is σ = 1311213404. Its totient is φ = 1311213402.

The previous prime is 1311213401. The next prime is 1311213419. The reversal of 1311213403 is 3043121131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1311213403 - 21 = 1311213401 is a prime.

Together with 1311213401, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1311213401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655606701 + 655606702.

It is an arithmetic number, because the mean of its divisors is an integer number (655606702).

Almost surely, 21311213403 is an apocalyptic number.

1311213403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311213403 is an equidigital number, since it uses as much as digits as its factorization.

1311213403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 1311213403 is about 36210.6807861990. The cubic root of 1311213403 is about 1094.5219107912.

Adding to 1311213403 its reverse (3043121131), we get a palindrome (4354334534).

The spelling of 1311213403 in words is "one billion, three hundred eleven million, two hundred thirteen thousand, four hundred three".