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13112141233 is a prime number
BaseRepresentation
bin11000011011000101…
…10110010110110001
31020211210210210022111
430031202312112301
5203323202004413
610005034405321
7642634235002
oct141542662661
936753723274
1013112141233
115619509864
12265b290841
13130c6a6869
148c55db1a9
1551b203d3d
hex30d8b65b1

13112141233 has 2 divisors, whose sum is σ = 13112141234. Its totient is φ = 13112141232.

The previous prime is 13112141227. The next prime is 13112141239. The reversal of 13112141233 is 33214121131.

13112141233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (13112141227) and next prime (13112141239).

It can be written as a sum of positive squares in only one way, i.e., 12631961664 + 480179569 = 112392^2 + 21913^2 .

It is a cyclic number.

It is not a de Polignac number, because 13112141233 - 221 = 13110044081 is a prime.

It is not a weakly prime, because it can be changed into another prime (13112141239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556070616 + 6556070617.

It is an arithmetic number, because the mean of its divisors is an integer number (6556070617).

Almost surely, 213112141233 is an apocalyptic number.

It is an amenable number.

13112141233 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112141233 is an equidigital number, since it uses as much as digits as its factorization.

13112141233 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 432, while the sum is 22.

Adding to 13112141233 its reverse (33214121131), we get a palindrome (46326262364).

The spelling of 13112141233 in words is "thirteen billion, one hundred twelve million, one hundred forty-one thousand, two hundred thirty-three".