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13112212103 is a prime number
BaseRepresentation
bin11000011011000110…
…00111101010000111
31020211210221101112022
430031203013222013
5203323211241403
610005040113355
7642634651424
oct141543075207
936753841468
1013112212103
115619558031
12265b30585b
13130c6ccbb3
148c5618d4b
1551b219d38
hex30d8c7a87

13112212103 has 2 divisors, whose sum is σ = 13112212104. Its totient is φ = 13112212102.

The previous prime is 13112212063. The next prime is 13112212109. The reversal of 13112212103 is 30121221131.

13112212103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13112212103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13112212109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556106051 + 6556106052.

It is an arithmetic number, because the mean of its divisors is an integer number (6556106052).

Almost surely, 213112212103 is an apocalyptic number.

13112212103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112212103 is an equidigital number, since it uses as much as digits as its factorization.

13112212103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13112212103 its reverse (30121221131), we get a palindrome (43233433234).

The spelling of 13112212103 in words is "thirteen billion, one hundred twelve million, two hundred twelve thousand, one hundred three".