13112301144335 has 4 divisors (see below), whose sum is σ = 15734761373208. Its totient is φ = 10489840915464.

The previous prime is 13112301144233. The next prime is 13112301144337. The reversal of 13112301144335 is 53344110321131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13112301144335 - 2²⁰ = 13112300095759 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13112301144337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1311230114429 + ... + 1311230114438.

It is an arithmetic number, because the mean of its divisors is an integer number (3933690343302).

Almost surely, 2^{13112301144335} is an apocalyptic number.

13112301144335 is a deficient number, since it is larger than the sum of its proper divisors (2622460228873).

13112301144335 is an equidigital number, since it uses as much as digits as its factorization.

13112301144335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2622460228872.

The product of its (nonzero) digits is 12960, while the sum is 32.

Adding to 13112301144335 its reverse (53344110321131), we get a palindrome (66456411465466).

The spelling of 13112301144335 in words is "thirteen trillion, one hundred twelve billion, three hundred one million, one hundred forty-four thousand, three hundred thirty-five".