Base | Representation |
---|---|
bin | 1011111011001111001010… |
… | …1101001100001011010111 |
3 | 1201102112011120120101001111 |
4 | 2332303302231030023113 |
5 | 3204313003400320043 |
6 | 43515414003035451 |
7 | 2522222214022504 |
oct | 276636255141327 |
9 | 51375146511044 |
10 | 13112312120023 |
11 | 41a599a3998a6 |
12 | 157930696bb87 |
13 | 7416411b1c7c |
14 | 3348d43104ab |
15 | 17b13474709d |
hex | becf2b4c2d7 |
13112312120023 has 2 divisors, whose sum is σ = 13112312120024. Its totient is φ = 13112312120022.
The previous prime is 13112312119993. The next prime is 13112312120071. The reversal of 13112312120023 is 32002121321131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13112312120023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13112312119976 and 13112312120003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112412120023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556156060011 + 6556156060012.
It is an arithmetic number, because the mean of its divisors is an integer number (6556156060012).
Almost surely, 213112312120023 is an apocalyptic number.
13112312120023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112312120023 is an equidigital number, since it uses as much as digits as its factorization.
13112312120023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 13112312120023 its reverse (32002121321131), we get a palindrome (45114433441154).
The spelling of 13112312120023 in words is "thirteen trillion, one hundred twelve billion, three hundred twelve million, one hundred twenty thousand, twenty-three".
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