Base | Representation |
---|---|
bin | 10011000101001011011… |
… | …111011001001111001111 |
3 | 11122100111222111010022011 |
4 | 103011023133121033033 |
5 | 132440400233440234 |
6 | 2442212122402051 |
7 | 163506353150362 |
oct | 23051337311717 |
9 | 4570458433264 |
10 | 1311231546319 |
11 | 4660aa02a182 |
12 | 192160960327 |
13 | 96857ca2b36 |
14 | 4766d0d00d9 |
15 | 24194ea0b64 |
hex | 1314b7d93cf |
1311231546319 has 2 divisors, whose sum is σ = 1311231546320. Its totient is φ = 1311231546318.
The previous prime is 1311231546223. The next prime is 1311231546343. The reversal of 1311231546319 is 9136451321131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1311231546319 - 227 = 1311097328591 is a prime.
It is a super-2 number, since 2×13112315463192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311231586319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655615773159 + 655615773160.
It is an arithmetic number, because the mean of its divisors is an integer number (655615773160).
Almost surely, 21311231546319 is an apocalyptic number.
1311231546319 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311231546319 is an equidigital number, since it uses as much as digits as its factorization.
1311231546319 is an evil number, because the sum of its binary digits is even.
The product of its digits is 58320, while the sum is 40.
The spelling of 1311231546319 in words is "one trillion, three hundred eleven billion, two hundred thirty-one million, five hundred forty-six thousand, three hundred nineteen".
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