1311232042453 has 2 divisors, whose sum is σ = 1311232042454. Its totient is φ = 1311232042452.

The previous prime is 1311232042441. The next prime is 1311232042457. The reversal of 1311232042453 is 3542402321131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1294138310404 + 17093732049 = 1137602^2 + 130743^2 .

It is an emirp because it is prime and its reverse (3542402321131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311232042453 - 2⁹ = 1311232041941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311232042457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655616021226 + 655616021227.

It is an arithmetic number, because the mean of its divisors is an integer number (655616021227).

Almost surely, 2^{1311232042453} is an apocalyptic number.

It is an amenable number.

1311232042453 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311232042453 is an equidigital number, since it uses as much as digits as its factorization.

1311232042453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 1311232042453 its reverse (3542402321131), we get a palindrome (4853634363584).

The spelling of 1311232042453 in words is "one trillion, three hundred eleven billion, two hundred thirty-two million, forty-two thousand, four hundred fifty-three".