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13112330204147 is a prime number
BaseRepresentation
bin1011111011001111001111…
…0010001011001111110011
31201102112012211121010210212
42332303303302023033303
53204313023013013042
643515415450414335
72522222523522056
oct276636362131763
951375184533725
1013112330204147
1141a59a9620759
121579310a313ab
13741644b74335
143348d689aa9d
1517b13611a482
hexbecf3c8b3f3

13112330204147 has 2 divisors, whose sum is σ = 13112330204148. Its totient is φ = 13112330204146.

The previous prime is 13112330204143. The next prime is 13112330204159. The reversal of 13112330204147 is 74140203321131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13112330204147 - 22 = 13112330204143 is a prime.

It is a super-3 number, since 3×131123302041473 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13112330204143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556165102073 + 6556165102074.

It is an arithmetic number, because the mean of its divisors is an integer number (6556165102074).

Almost surely, 213112330204147 is an apocalyptic number.

13112330204147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112330204147 is an equidigital number, since it uses as much as digits as its factorization.

13112330204147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 32.

Adding to 13112330204147 its reverse (74140203321131), we get a palindrome (87252533525278).

The spelling of 13112330204147 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty million, two hundred four thousand, one hundred forty-seven".