Base | Representation |
---|---|
bin | 1011111011001111001111… |
… | …0010001011001111110011 |
3 | 1201102112012211121010210212 |
4 | 2332303303302023033303 |
5 | 3204313023013013042 |
6 | 43515415450414335 |
7 | 2522222523522056 |
oct | 276636362131763 |
9 | 51375184533725 |
10 | 13112330204147 |
11 | 41a59a9620759 |
12 | 1579310a313ab |
13 | 741644b74335 |
14 | 3348d689aa9d |
15 | 17b13611a482 |
hex | becf3c8b3f3 |
13112330204147 has 2 divisors, whose sum is σ = 13112330204148. Its totient is φ = 13112330204146.
The previous prime is 13112330204143. The next prime is 13112330204159. The reversal of 13112330204147 is 74140203321131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13112330204147 - 22 = 13112330204143 is a prime.
It is a super-3 number, since 3×131123302041473 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13112330204143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556165102073 + 6556165102074.
It is an arithmetic number, because the mean of its divisors is an integer number (6556165102074).
Almost surely, 213112330204147 is an apocalyptic number.
13112330204147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112330204147 is an equidigital number, since it uses as much as digits as its factorization.
13112330204147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 13112330204147 its reverse (74140203321131), we get a palindrome (87252533525278).
The spelling of 13112330204147 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty million, two hundred four thousand, one hundred forty-seven".
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