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13112331431021 is a prime number
BaseRepresentation
bin1011111011001111001111…
…0110110110110001101101
31201102112012220220110202122
42332303303312312301231
53204313023321243041
643515415533002325
72522222540122004
oct276636366666155
951375186813678
1013112331431021
1141a59aa2894a9
1215793113233a5
137416451b38b4
143348d6ad9c3b
1517b1362adc4b
hexbecf3db6c6d

13112331431021 has 2 divisors, whose sum is σ = 13112331431022. Its totient is φ = 13112331431020.

The previous prime is 13112331431009. The next prime is 13112331431083. The reversal of 13112331431021 is 12013413321131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8737285692100 + 4375045738921 = 2955890^2 + 2091661^2 .

It is a cyclic number.

It is not a de Polignac number, because 13112331431021 - 210 = 13112331429997 is a prime.

It is a super-3 number, since 3×131123314310213 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13112331431321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556165715510 + 6556165715511.

It is an arithmetic number, because the mean of its divisors is an integer number (6556165715511).

Almost surely, 213112331431021 is an apocalyptic number.

It is an amenable number.

13112331431021 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112331431021 is an equidigital number, since it uses as much as digits as its factorization.

13112331431021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 26.

Adding to 13112331431021 its reverse (12013413321131), we get a palindrome (25125744752152).

It can be divided in two parts, 13112 and 331431021, that added together give a palindrome (331444133).

The spelling of 13112331431021 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty-one million, four hundred thirty-one thousand, twenty-one".