13112352127951 has 2 divisors, whose sum is σ = 13112352127952. Its totient is φ = 13112352127950.

The previous prime is 13112352127793. The next prime is 13112352127957. The reversal of 13112352127951 is 15972125321131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13112352127951 - 2³³ = 13103762193359 is a prime.

It is a super-2 number, since 2×13112352127951² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13112352127898 and 13112352127907.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13112352127957) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556176063975 + 6556176063976.

It is an arithmetic number, because the mean of its divisors is an integer number (6556176063976).

Almost surely, 2^{13112352127951} is an apocalyptic number.

13112352127951 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112352127951 is an equidigital number, since it uses as much as digits as its factorization.

13112352127951 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 113400, while the sum is 43.

The spelling of 13112352127951 in words is "thirteen trillion, one hundred twelve billion, three hundred fifty-two million, one hundred twenty-seven thousand, nine hundred fifty-one".