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13112403013 is a prime number
BaseRepresentation
bin11000011011000111…
…10110010001000101
31020211211022002102001
430031203312101011
5203323233344023
610005044145301
7642636405133
oct141543662105
936754262361
1013112403013
115619678506
12265b398231
13130c768a68
148c5668753
1551b2566ad
hex30d8f6445

13112403013 has 2 divisors, whose sum is σ = 13112403014. Its totient is φ = 13112403012.

The previous prime is 13112402981. The next prime is 13112403037. The reversal of 13112403013 is 31030421131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9145670689 + 3966732324 = 95633^2 + 62982^2 .

It is an emirp because it is prime and its reverse (31030421131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13112403013 - 25 = 13112402981 is a prime.

It is a super-2 number, since 2×131124030132 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13112403113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556201506 + 6556201507.

It is an arithmetic number, because the mean of its divisors is an integer number (6556201507).

Almost surely, 213112403013 is an apocalyptic number.

It is an amenable number.

13112403013 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112403013 is an equidigital number, since it uses as much as digits as its factorization.

13112403013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13112403013 its reverse (31030421131), we get a palindrome (44142824144).

The spelling of 13112403013 in words is "thirteen billion, one hundred twelve million, four hundred three thousand, thirteen".