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13112403334 = 26556201667
BaseRepresentation
bin11000011011000111…
…10110010110000110
31020211211022002211221
430031203312112012
5203323233401314
610005044150554
7642636406102
oct141543662606
936754262757
1013112403334
115619678778
12265b39845a
13130c768c54
148c5668902
1551b256824
hex30d8f6586

13112403334 has 4 divisors (see below), whose sum is σ = 19668605004. Its totient is φ = 6556201666.

The previous prime is 13112403319. The next prime is 13112403407. The reversal of 13112403334 is 43330421131.

13112403334 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43330421131 = 371171092463.

It is a junction number, because it is equal to n+sod(n) for n = 13112403299 and 13112403308.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3278100832 + ... + 3278100835.

It is an arithmetic number, because the mean of its divisors is an integer number (4917151251).

Almost surely, 213112403334 is an apocalyptic number.

13112403334 is a deficient number, since it is larger than the sum of its proper divisors (6556201670).

13112403334 is an equidigital number, since it uses as much as digits as its factorization.

13112403334 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6556201669.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13112403334 its reverse (43330421131), we get a palindrome (56442824465).

The spelling of 13112403334 in words is "thirteen billion, one hundred twelve million, four hundred three thousand, three hundred thirty-four".

Divisors: 1 2 6556201667 13112403334