Base | Representation |
---|---|
bin | 1011111011001111100001… |
… | …0000010110001100010111 |
3 | 1201102112102001202110012001 |
4 | 2332303320100112030113 |
5 | 3204313201214102132 |
6 | 43515431130340131 |
7 | 2522224424255356 |
oct | 276637020261427 |
9 | 51375361673161 |
10 | 13112405222167 |
11 | 41a5a379a9919 |
12 | 1579331b8a647 |
13 | 74165757bbb4 |
14 | 33490282799d |
15 | 17b13c9d7ce7 |
hex | becf8416317 |
13112405222167 has 2 divisors, whose sum is σ = 13112405222168. Its totient is φ = 13112405222166.
The previous prime is 13112405222117. The next prime is 13112405222219. The reversal of 13112405222167 is 76122250421131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13112405222167 - 219 = 13112404697879 is a prime.
It is a super-3 number, since 3×131124052221673 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112405222117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556202611083 + 6556202611084.
It is an arithmetic number, because the mean of its divisors is an integer number (6556202611084).
Almost surely, 213112405222167 is an apocalyptic number.
13112405222167 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112405222167 is an equidigital number, since it uses as much as digits as its factorization.
13112405222167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40320, while the sum is 37.
Adding to 13112405222167 its reverse (76122250421131), we get a palindrome (89234655643298).
The spelling of 13112405222167 in words is "thirteen trillion, one hundred twelve billion, four hundred five million, two hundred twenty-two thousand, one hundred sixty-seven".
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